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Helicopter Flight Simulation Motion Platform Requirements(66)

时间:2011-11-12 12:15来源:蓝天飞行翻译 作者:admin
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Table C1. Average pilot compensation ratings for yaw experiment Task 1.
Pilot (i) Translational on (j)  Rotational on (k)  Average rating (Y) 
1 0  0  2.67 
1 0  1  2.25 
1 1  0  1.75 
1 1  1  1.75 
2 0  0  2.25 
2 0  1  1.75 
2 1  0  0.75 
2 1  1  0.00 
3 0  0  1.25 
3 0  1  1.25 
3 1  0  1.00 
3 1  1  1.00 
4 0  0  3.00 
4 0  1  3.00 
4 1  0  3.00 
4 1  1  3.00 
5 0  0  2.50 
5 0  1  2.50 
5 1  0  0.25 
5 1  1  0.00 
6 0  0  1.75 
6 0  1  2.00 
6 1  0  1.25 
6 1  1  1.00 

To determine whether the differences noted owing to translational motion are statistically significant, the ratio MStrans / MStrans/pilot is formed. The numerator of this ratio, MStrans is the between-groups mean square. The denomi-nator of this ratio, MStrans/pilot, is the population error variance. The higher this ratio, the more likely that the differences between the two translational configurations are due to the effect of translational motion and that they are not random results. The relations for these terms are:
MS
trans
F = (C1)
MS
trans / pilot
SS
trans
MS = (C2)
trans
(a . 1)
SS
trans / pilot
MS = (C3)
trans / pilot
(a .1)( n .1) 2
..
∑∑ ∑ Y .
. ijk
..
ji k
SS = (C4)
trans / pilot
b CSS .SS
..
trans pilot
where
2
..
∑∑∑ Y .
. ijk j .ik .
SS =.C (C5)
trans
nb
and for Task 1 in the Yaw experiment:
2
..
Y
∑∑∑ . ijk . i .jk .
SSpilot =.C (C6)
ab 2
.. .∑∑∑Yijk ..i jk .
C = (C7)
abn i =1,..., 6 =pilot j =01 =translational configuration (off or on)
, k = 0,1 = rotational configuration (off or on) a = 2 = number of lateral configurations b = 2 = number of rotational configurations n = 6 = number of pilots
Using the values from table C1, then the equations become
(. )2
40 92
C ==69 77
. (C8)()()( )
226 . 222 .
(. ) +(475 . ) +(450 )842 .
..
. 222 .
+(.12 00 ) +(. ) +(6 00 .
525 )
.. (C9)
=
SSpilot 22
()() . . =10 55
6977 .
(.)2 +14 75 )2
2617 (.
=.69 77 . =5 43 (C10)
.
SStrans
()( ) 62
. 222 .
(. ) +(. ) +(250 )492 400 .
..
 
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